SQL Assignment Help | SQL Homework help

Updated: Aug 5, 2019



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SQL Assignment 1

1. List customers whose name begins with B.

2. List customers with a credit limit of $10000 or more.

3. List item number, description, and the value of on-hand stock (price x quantity) of each item in the

CATEGORY: TOY. Rename the column to Value by using AS.

4. How many items are there in each CATEGORY

5. What is the total value (price*quantity on hand) of stock in each CATEGORY

6. How many customers are there?

7. How many items are there?

8. List all customers in postal codes: 90085, 90097 & 90098.


Assignment 2

9. List all customers (number and name) who placed orders

10. List all the items ordered by each customer - Customer_num, customer_name, item_num, description

11. Which customers ordered GME CATEGORY items

12. What is the Total Value of orders placed by each customer.

13. What is the value of orders placed for each item: List item_num, description, and totalValue

14. What is the average quoted_price of each item in the orders placed.

15. Which reps sold the part with the description: Skittles (please see the real data in the relevant table

and ensure that the capitalization matches).

16. Which customers ordered item: FD11.


Assignment 3

Give the answer of each problems into the comments section as per given below data tables.


CREATE TABLE customer

(

custid VARCHAR(6),

fname VARCHAR(30),

mname VARCHAR(30),

ltname VARCHAR(30),

city VARCHAR(15),

mobileno VARCHAR(10),

occupation VARCHAR(10),

dob DATE,

CONSTRAINT customer_custid_pk PRIMARY KEY(custid)

);


CREATE TABLE branch

(

bid VARCHAR(6),

bname VARCHAR(30),

bcity VARCHAR(30),

CONSTRAINT branch_bid_pk PRIMARY KEY(bid)

);


CREATE TABLE account

(

acnumber VARCHAR(6),

custid VARCHAR(6),

bid VARCHAR(6),

opening_balance INT(7),

aod DATE,

atype VARCHAR(10),

astatus VARCHAR(10),

CONSTRAINT account_acnumber_pk PRIMARY KEY(acnumber),

CONSTRAINT account_custid_fk FOREIGN KEY(custid) REFERENCES customer(custid),

CONSTRAINT account_bid_fk FOREIGN KEY(bid) REFERENCES branch(bid)

);


CREATE TABLE trandetails

(

tnumber VARCHAR(6),

acnumber VARCHAR(6),

dot DATE,

medium_of_transaction VARCHAR(20),

transaction_type VARCHAR(20),

transaction_amount INT(7),

CONSTRAINT trandetails_tnumber_pk PRIMARY KEY(tnumber),

CONSTRAINT trandetails_acnumber_fk FOREIGN KEY(acnumber) REFERENCES account(acnumber)

);


CREATE TABLE loan

(

custid VARCHAR(6),

bid VARCHAR(6),

loan_amount INT(7),

CONSTRAINT loan_customer_custid_bid_pk PRIMARY KEY(custid,bid),

CONSTRAINT loan_custid_fk FOREIGN KEY(custid) REFERENCES customer(custid),

CONSTRAINT loan_bid_fk FOREIGN KEY(bid) REFERENCES branch(bid)

);


INSERT INTO customer VALUES('C00001','Ramesh','Chandra','Sharma','Delhi','9543198345','Service','1976-12-06');

INSERT INTO customer VALUES('C00002','Avinash','Sunder','Minha','Delhi','9876532109','Service','1974-10-16');

INSERT INTO customer VALUES('C00003','Rahul',null,'Rastogi','Delhi','9765178901','Student','1981-09-26');

INSERT INTO customer VALUES('C00004','Parul',null,'Gandhi','Delhi','9876532109','Housewife','1976-11-03');

INSERT INTO customer VALUES('C00005','Naveen','Chandra','Aedekar','Mumbai','8976523190','Service','1976-09-19');

INSERT INTO customer VALUES('C00006','Chitresh',null,'Barwe','Mumbai','7651298321','Student','1992-11-06');

INSERT INTO customer VALUES('C00007','Amit','Kumar','Borkar','Mumbai','9875189761','Student','1981-09-06');

INSERT INTO customer VALUES('C00008','Nisha',null,'Damle','Mumbai','7954198761','Service','1975-12-03');

INSERT INTO customer VALUES('C00009','Abhishek',null,'Dutta','Kolkata','9856198761','Service','1973-05-22');

INSERT INTO customer VALUES('C00010','Shankar',null,'Nair','Chennai','8765489076','Service','1976-07-12');


INSERT INTO branch VALUES('B00001','Asaf ali road','Delhi');

INSERT INTO branch VALUES('B00002','New delhi main branch','Delhi');

INSERT INTO branch VALUES('B00003','Delhi cantt','Delhi');

INSERT INTO branch VALUES('B00004','Jasola','Delhi');

INSERT INTO branch VALUES('B00005','Mahim','Mumbai');

INSERT INTO branch VALUES('B00006','Vile parle','Mumbai');

INSERT INTO branch VALUES('B00007','Mandvi','Mumbai');

INSERT INTO branch VALUES('B00008','Jadavpur','Kolkata');

INSERT INTO branch VALUES('B00009','Kodambakkam','Chennai');


INSERT INTO account VALUES('A00001','C00001','B00001',1000,'2012-12-15','Saving','Active');

INSERT INTO account VALUES('A00002','C00002','B00001',1000,'2012-06-12','Saving','Active');

INSERT INTO account VALUES('A00003','C00003','B00002',1000,'2012-05-17','Saving','Active');

INSERT INTO account VALUES('A00004','C00002','B00005',1000,'2013-01-27','Saving','Active');

INSERT INTO account VALUES('A00005','C00006','B00006',1000,'2012-12-17','Saving','Active');

INSERT INTO account VALUES('A00006','C00007','B00007',1000,'2010-08-12','Saving','Suspended');

INSERT INTO account VALUES('A00007','C00007','B00001',1000,'2012-10-02','Saving','Active');

INSERT INTO account VALUES('A00008','C00001','B00003',1000,'2009-11-09','Saving','Terminated');

INSERT INTO account VALUES('A00009','C00003','B00007',1000,'2008-11-30','Saving','Terminated');

INSERT INTO account VALUES('A00010','C00004','B00002',1000,'2013-03-01','Saving','Active');


INSERT INTO trandetails VALUES('T00001','A00001','2013-01-01','Cheque','Deposit',2000);

INSERT INTO trandetails VALUES('T00002','A00001','2013-02-01','Cash','Withdrawal',1000);

INSERT INTO trandetails VALUES('T00003','A00002','2013-01-01','Cash','Deposit',2000);

INSERT INTO trandetails VALUES('T00004','A00002','2013-02-01','Cash','Deposit',3000);

INSERT INTO trandetails VALUES('T00005','A00007','2013-01-11','Cash','Deposit',7000);

INSERT INTO trandetails VALUES('T00006','A00007','2013-01-13','Cash','Deposit',9000);

INSERT INTO trandetails VALUES('T00007','A00001','2013-03-13','Cash','Deposit',4000);

INSERT INTO trandetails VALUES('T00008','A00001','2013-03-14','Cheque','Deposit',3000);

INSERT INTO trandetails VALUES('T00009','A00001','2013-03-21','Cash','Withdrawal',9000);

INSERT INTO trandetails VALUES('T00010','A00001','2013-03-22','Cash','Withdrawal',2000);

INSERT INTO trandetails VALUES('T00011','A00002','2013-03-25','Cash','Withdrawal',7000);

INSERT INTO trandetails VALUES('T00012','A00007','2013-03-26','Cash','Withdrawal',2000);


INSERT INTO loan VALUES('C00001','B00001',100000);

INSERT INTO loan VALUES('C00002','B00002',200000);

INSERT INTO loan VALUES('C00009','B00008',400000);

INSERT INTO loan VALUES('C00010','B00009',500000);

INSERT INTO loan VALUES('C00001','B00003',600000);

INSERT INTO loan VALUES('C00002','B00001',600000);


Problems:


Problem #1:

Write a query to display the customer number , firstname, customer’s date of birth . Display in a sorted order of date of birth year and within that sort by firstname.


Problem #2:

Write a query to display customer’s number, first name and middle name. The customer’s who don’t have middle name, for them display the last name. Give the alias name as Cust_Name.

Problem#3:

Write a query to display account number, customer’s number, customer’s firstname,lastname,account opening date.


Problem # 4:

Write a query to display the number of customer’s from Delhi. Give the count an alias name of Cust_Count.


Problem # 5:

Write a query to display the customer number, customer firstname,account number for the customer’s whose accounts were created after 15th of any month.


Problem # 6:

Write a query to display the female customers firstname, city and account number who are not into business, service or studies.


Problem # 7:

Write a query to display city name and count of branches in that city. Give the count of branches an alias name of Count_Branch.


Problem # 8:

Write a query to display account id, customer’s firstname, customer’s lastname for the customer’s whose account is Active.


Problem # 9:

Write a query to display the customer’s number, customer’s firstname, branch id and loan amount for people who have taken loans.


Problem # 10:

Write a query to display customer number, customer name, account number where the account status is terminated.


Problem#1:

Write a query to display the total number of withdrawals and total number of deposits being done by customer whose registration is C00001. Give the count an alias name of Trans_Count.


Problem # 2:

Write a query to display the customer’s number, customer’s firstname, customer’s city and branch city where the city of the customer and city of the branch is different.


Problem # 3:

Write a query to display the customer number, customer firstname, customer lastname who has taken loan from more then 1 bank.


Problem # 4:

Write a query to display the number of client who have asked for loans but they don’t have any account in the bank though they are registered customers. Give the count an alias name of Count.


Problem # 5:

Write a query to display account id, and total amount deposited by each account holder ( Including the opening balance ). Give the total amount deposited an alias name of Deposit_Amount.


Problem # 6:

Write a query to the count the number of customers who have registration but no account in the bank.

Give the alias name as Count_Customer.


Problem # 7:

Write a query to display citywise, branchwise count of accounts. For the branch where we don’t have any records display 0.


Problem # 8:

Write a query to display the customer’s firstname who have more then 1 account.


Problem # 9:

Write a query to display the customer’s firstname who have multiple accounts atleast in 2 banks.


Problem # 10:

Display the customer number, customer name, account number and number of transactions being made by a customer. Give the alias name for number of transactions as Count_Trans


Problem # 1:

Write a query to display the account number who has done the highest transaction.


For example the account A00023 has done 5 transactions i.e. suppose 3 withdrawal and 2 deposits. Whereas the account A00024 has done 3 transactions i.e. suppose 2 withdrawals and 1 deposit. So account number of A00023 should be displayed.


Problem #2:

Write a query to show the branch name,branch city where we have the maximum customers.


For example the branch B00019 has 3 customers, B00020 has 7 and B00021 has 10. So branch id B00021 is having maximum customers. B00021 is suppose for Koramangla branch Bangalore. So Koramangla branch should be displayed along with city name Bangalore.

Problem#3:

Write a query to show the balance amount for account number A00001.

Note: Balance amount includes account opening balance also.


For example A00015 is having an opening balance of 1000. A00015 has deposited 2000 on 2012-06-12 and deposited 3000 on 2012-07-13. The same account has drawn money of 500 on 2012-08-12 , 500 on 2012-09-15, 1000 on 2012-12-17. So balance amount is 4000 i.e (1000 (opening balance)+2000+3000 ) – (500+500+1000).


Problem # 4:

Write a query to display all those account number, deposit, withdrawal where withdrawal is more then deposit amount.


For example A00011 deposited 2000 rupees on 2012-12-01 and 3000 rupees on 2012-12-02. The same account i.e A00011 withdrawn 3000 rupees on 2013-01-01 and 7000 rupees on 2013-01-03. So the total deposited amount is 5000 and total withdrawal amount is 10000. So withdrawal amount is more then deposited for account number A00011.


Problem # 5:

Write a query to display the customer number, firstname, lastname for those client where total loan amount taken is maximum and at least taken from 2 banks.


For example the customer C00012 took a loan of 100000 from bank branch with id B00009 and C00012

Took a loan of 500000 from bank branch with id B00010. So total loan amount for customer C00012 is

600000. C00013 took a loan of 100000 from bank branch B00009 and 200000 from bank branch B00011.

So total loan taken is 300000. So loan taken by C00012 is more then C00013.


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